• Zagorath
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    1 year ago

    This is exactly right. It’s not a law of maths in the way that 1+1=2 is a law. It’s a convention of notation.

    The vast majority of the time, mathematicians use implicit multiplication (aka multiplication indicated by juxtaposition) at a higher priority than division. This makes sense when you consider something like 1/2x. It’s an extremely common thing to want to write, and it would be a pain in the arse to have to write brackets there every single time. So 1/2x is universally interpreted as 1/(2x), and not (1/2)x, which would be x/2.

    The same logic is what’s used here when people arrive at an answer of 1.

    If you were to survey a bunch of mathematicians—and I mean people doing academic research in maths, not primary school teachers—you would find the vast majority of them would get to 1. However, you would first have to give a way to do that survey such that they don’t realise the reason they’re being surveyed, because if they realise it’s over a question like this they’ll probably end up saying “it’s deliberately ambiguous in an attempt to start arguments”.

      • Zagorath
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        1 year ago

        So are you suggesting that Richard Feynman didn’t “deal with maths a lot”, then? Because there definitely exist examples where he worked within the limitations of the medium he was writing in (namely: writing in places where using bar fractions was not an option) and used juxtaposition for multiplication bound more tightly than division.

        Here’s another example, from an advanced mathematics textbook:

        Both show the use of juxtaposition taking precedence over division.

        I should note that these screenshots are both taken from this video where you can see them with greater context and discussion on the subject.

        • custard_swollower@lemmy.world
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          1 year ago

          Mind you, Feynmann clearly states this is a fraction, and denotes it with “/” likely to make sure you treat it as a fraction.

          • barsoap@lemm.ee
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            1 year ago

            Yep with pen and paper you always write fractions as actual fractions to not confuse yourself, never a division in sight, while with papers you have a page limit to observe. Length of the bars disambiguates precedence which is important because division is not associative; a/(b/c) /= (a/b)/c. “calculate from left to right” type of rules are awkward because they prevent you from arranging stuff freely for readability. None of what he writes there has more than one division in it, chances are that if you see two divisions anywhere in his work he’s using fractional notation.

            Multiplication by juxtaposition not binding tightest is something I have only ever heard from Americans citing strange abbreviations as if they were mathematical laws. We were never taught any such procedural stuff in school: If you understand the underlying laws you know what you can do with an expression and what not, it’s the difference between teaching calculation and teaching algebra.

            • never a division in sight

              There is, especially if you’re dividing by a fraction! Division and fractions aren’t the same thing.

              if you see two divisions anywhere in his work he’s using fractional notation

              Not if it actually is a division and not a fraction. There’s no problem with having multiple divisions in a single expression.

              • barsoap@lemm.ee
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                8 months ago

                Division and fractions aren’t the same thing.

                Semantically, yes they are. Syntactically they’re different.

                  • barsoap@lemm.ee
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                    8 months ago

                    That’s syntax.

                    …let me take this seriously for a second.

                    The claim “Division and fractions are semantically distinct” implies that they are provably distinct functions, we can use the usual set-theoretic definition of those. Distinctness of functions implies the presence of pair n, m, elements of an appropriate set, say, the natural numbers without zero for convenience, such that (excuse my Haskell) div n m /= fract n m, where /= is the appropriate inequality of the result set (the rational numbers, in this example, which happens to be decidable which is also convenient).

                    Can you give me such a pair of numbers? We can start to enumerate the problem. Does div 1 1 /= fract 1 1 hold? No, the results are equal, both are 1. How about div 1 2 /= fract 1 2? Neither, the results are both the same rational number. I leave exploring the rest of the possibilities as an exercise and apologise for the smugness.

          • denotes it with “/” likely to make sure you treat it as a fraction

            It’s not the slash which makes it a fraction - in fact that is interpreted as division - but the fact that there is no space between the 2 and the square root - that makes it a single term (therefore we are dividing by the whole term). Terms are separated by operators (2 and the square root NOT separated by anything) and joined by grouping symbols (brackets, fraction bars).

        • itslilith@lemmy.blahaj.zone
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          8 months ago

          Fractions and division aren’t the same thing.

          Are you for real? A fraction is a shorthand for division with stronger (and therefore less ambiguous) order of operations

          • Are you for real?

            Yes, I’m a Maths teacher.

            A fraction is a shorthand for division with stronger (and therefore less ambiguous) order of operations

            I added emphasis to where you nearly had it.

            ½ is a single term. 1÷2 is 2 terms. Terms are separated by operators (division in this case) and joined by grouping symbols (fraction bars, brackets).

            1÷½=2

            1÷1÷2=½ (must be done left to right)

            Thus 1÷2 and ½ aren’t the same thing (they are equal in simple cases, but not the same thing), but ½ and (1÷2) are the same thing.

    • gordon@lemmy.world
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      1 year ago

      So 1/2x is universally interpreted as 1/(2x), and not (1/2)x, which would be x/2.

      Sorry but both my phone calculator and TI-84 calculate 1/2X to be the same thing as X/2. It’s simply evaluating the equation left to right since multiplication and division have equal priorities.

      X = 5

      Y = 1/2X => (1/2) * X => X/2

      Y = 2.5

      If you want to see Y = 0.1 you must explicitly add parentheses around the 2X.

      Before this thread I have never heard of implicit operations having higher priority than explicit operations, which honestly sounds like 100% bogus anyway.

      You are saying that an implied operation has higher priority than one which I am defining as part of the equation with an operator? Bogus. I don’t buy it. Seriously when was this decided?

      I am no mathematics expert, but I have taken up to calc 2 and differential equations and never heard this “rule” before.

      • Incandemon@lemmy.ca
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        1 year ago

        I can say that this is a common thing in engineering. Pretty much everyone I know would treat 1/2x as 1/(2x).

        Which does make it a pain when punched into calculators to remember the way we write it is not necessarily the right way to enter it. So when put into matlab or calculators or what have you the number of brackets can become ridiculous.

        • mcteazy@sh.itjust.works
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          1 year ago

          I’m an engineer. Writing by hand I would always use a fraction. If I had to write this in an email or something (quickly and informally) either the context would have to be there for someone to know which one I meant or I would use brackets. I certainly wouldn’t just wrote 1/2x and expect you to know which one I meant with no additional context or brackets

      • Sorry but both my phone calculator and TI-84 calculate 1/2X

        …and they’re both wrong, because they are disobeying the order of operations rules. Almost all e-calculators are wrong, whereas almost all physical calculators do it correctly (the notable exception being Texas Instruments).

        You are saying that an implied operation has higher priority than one which I am defining as part of the equation with an operator? Bogus. I don’t buy it. Seriously when was this decided?

        The rules of Terms and The Distributive Law, somewhere between 100-400 years ago, as per Maths textbooks of any age. Operators separate terms.

        I am no mathematics expert… never heard this “rule” before.

        I’m a High School Maths teacher/tutor, and have taught it many times.

    • It’s not a law of maths in the way that 1+1=2 is a law

      Yes it is, literally! The Distributive Law, and Terms. Also 1+1=2 isn’t a Law, but a definition.

      So 1/2x is universally interpreted as 1/(2x)

      Correct, Terms - ab=(axb).

      people doing academic research in maths, not primary school teachers

      Don’t ask either - this is actually taught in Year 7.

      if they realise it’s over a question like this they’ll probably end up saying “it’s deliberately ambiguous in an attempt to start arguments”

      The university people, who’ve forgotten the rules of Maths, certainly say that, but I doubt Primary School teachers would say that - they teach the first stage of order of operations, without coefficients, then high school teachers teach how to do brackets with coefficients (The Distributive Law).